Related articles |
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A question about Dominators rsherry8@home.com (Robert Sherry) (2001-12-15) |
Re:A question about Dominators kvinay@ip.eth.net (kvinay) (2001-12-20) |
Re: A question about Dominators vbdis@aol.com (2001-12-20) |
Re: A question about Dominators Martin.Ward@durham.ac.uk (2001-12-20) |
Re: A question about Dominators sweeks@acm.org (2001-12-20) |
Re: A question about Dominators jeremy.wright@merant.com (Jeremy Wright) (2001-12-20) |
From: | vbdis@aol.com (VBDis) |
Newsgroups: | comp.compilers |
Date: | 20 Dec 2001 00:33:56 -0500 |
Organization: | AOL Bertelsmann Online GmbH & Co. KG http://www.germany.aol.com |
References: | 01-12-067 |
Keywords: | analysis |
Posted-Date: | 20 Dec 2001 00:33:56 EST |
"Robert Sherry" <rsherry8@home.com>schreibt:
>The basic idea of the first approach is that node a
>dominates node b if and only if a=b or a is the unique immediate predecessor
>of b or b has more then one immediate predecessor and for all immediate
>predecessors c of b, c is not equal to a and a dominates c.
IMO it's a matter of taste/convention, whether a node dominates itself
(a=b). But I definitely see no reason, why the dominator cannot be
one of multiple immediate predecessors.
In a graph with the edges (a,b), (a,c), (b,c) node a dominates both
nodes b and c.
So the idea should read:
Node a dominates node b if a=b, or for all immediate predecessors c of b, a
dominates c.
Now the case a=b also makes sense, since when node a is an immediate
predecessor of b, then node a dominates itself (as predecessor c of b). It's
not required that a<>c, and a single predecessor is only a special case of
multiple predecessors.
BTW, do you have an equivalent definition or idea for post-dominators?
DoDi
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