Related articles |
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A question about Dominators rsherry8@home.com (Robert Sherry) (2001-12-15) |
Re:A question about Dominators kvinay@ip.eth.net (kvinay) (2001-12-20) |
Re: A question about Dominators vbdis@aol.com (2001-12-20) |
Re: A question about Dominators Martin.Ward@durham.ac.uk (2001-12-20) |
Re: A question about Dominators sweeks@acm.org (2001-12-20) |
Re: A question about Dominators jeremy.wright@merant.com (Jeremy Wright) (2001-12-20) |
From: | "Robert Sherry" <rsherry8@home.com> |
Newsgroups: | comp.compilers |
Date: | 15 Dec 2001 00:38:53 -0500 |
Organization: | Excite@Home - The Leader in Broadband http://home.com/faster |
Keywords: | analysis, books, question |
Posted-Date: | 15 Dec 2001 00:38:52 EST |
The following paragraph is from the book Advanced Compiler Design
Implementation by Steven S. Muchnick. I can be found on page 182.
We give two approaches to computing the set of dominators of each node
in a flowgraph. The basic idea of the first approach is that node a
dominates node b if and only if a=b or a is the unique immediate predecessor
of b or b has more then one immediate predecessor and for all immediate
predecessors c of b, c is not equal to a and a dominates c.
I believe that the above statement is incorrect. Please consider the
following flowgraph.
Nodes{ a, b, c, d, e }
Edges{ (a,c), (a,d), (c,e), (d,e), (e,b) )
a is the start node
In this case, a dominates b. However, it violates the if and only if given
above since b has a unique predecessor. The believe the correct statement
would be:
The basic idea of the first approach is that node a dominates
node b if and only if a=b or a is the unique immediate predecessor of
b or for all immediate predecessors c of b, c is not equal to a and a
dominates c.
Please comment.
Robert Sherry
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