Related articles |
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Modulo optimizations gmarshal@globalnet.co.uk (Graham Marshall) (1999-10-04) |
Re: Modulo optimizations jgk@jgk.org (Joe Keane) (1999-10-11) |
Re: Modulo optimizations torbenm@diku.dk (1999-10-13) |
Re: Modulo optimizations chase@world.std.com (David Chase) (1999-10-13) |
Re: Modulo optimizations ger@informatik.uni-bremen.de (George Russell) (1999-10-14) |
Re: Modulo optimizations harley@corton.inria.fr (Robert Harley) (1999-10-14) |
Re:Modulo optimizations Wilco.Dijkstra@arm.com (Wilco Dijkstra) (1999-10-19) |
Re: Modulo optimizations harley@corton.inria.fr (Robert Harley) (1999-10-21) |
Re: Modulo optimizations Peter-Lawrence.Montgomery@cwi.nl (1999-10-27) |
From: | Robert Harley <harley@corton.inria.fr> |
Newsgroups: | comp.compilers |
Date: | 14 Oct 1999 01:22:48 -0400 |
Organization: | I.N.R.I.A Rocquencourt |
References: | 99-10-017 99-10-056 |
Keywords: | arithmetic, optimize |
torbenm@diku.dk (Torben AEgidius Mogensen) writes:
> After this (if I haven't made any mistakes along the way), sum
> contains x%3.
It looks like it is in 0..3 so you need a final step to reduce to 0..2.
Here is another variant (for 32-bit unsigned ints):
static unsigned mod3(unsigned x) {
static const unsigned tab[18] = { 0,1,2,0,1,2,0,1,2,0,1,2,0,1,2,0,1,2 };
x = (x & 0xFFFF)+(x>>16);
x = (x & 255)+(x>>8);
x = (x & 15)+(x>>4);
x = (x & 3)+(x>>2);
return tab[x];
} /* end function mod3 */
Bye,
Rob.
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