Re: Defining polymorphism vs. overloading

compilers-sender@esegue.segue.boston.ma.us
Mon, 03 Sep 90 00:36:42 GMT

          From comp.compilers

Related articles
Defining polymorphism vs. overloading oliver@karakorum.berkeley.edu (1990-08-30)
Re: Defining polymorphism vs. overloading burley@world.std.com (1990-09-01)
Re: Defining polymorphism vs. overloading wright@gefion.rice.edu (1990-09-02)
Re: Defining polymorphism vs. overloading compilers-sender@esegue.segue.boston.ma.us (1990-09-03)
Re: Defining polymorphism vs. overloading hrubin@l.cc.purdue.edu (1990-09-03)
Re: Defining polymorphism vs. overloading px@fctunl.rccn.pt (1990-09-03)
Re: Defining polymorphism vs. overloading plph@caen.engin.umich.edu (1990-09-03)
Re: Defining polymorphism vs. overloading daveg@near.cs.caltech.edu (1990-09-03)
Re: Defining polymorphism vs. overloading dmw9q@uvacs.cs.Virginia.EDU (1990-09-05)
Re: Defining polymorphism vs. overloading pase@orville.nas.nasa.gov (1990-09-06)
[13 later articles]
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Newsgroups: comp.compilers
From: compilers-sender@esegue.segue.boston.ma.us
In-Reply-To: oliver@karakorum.berkeley.edu's message of 31 Aug 90 04:19:43 GMT
Keywords: design, polymorphism
Organization: Compilers Central
References: <9008310419.AA06194@karakorum.berkeley.edu>
Date: Mon, 03 Sep 90 00:36:42 GMT

In article <9008310419.AA06194@karakorum.berkeley.edu>
oliver@karakorum.berkeley.edu (Oliver Sharp) conjectures:


          o Overloading means using the same name (or symbol) to invoke different
              code depending on the types of the arguments (or operands). So, an example
              is +, which may do radically different things for integers, floats, and
              complex numbers. In other words, you have different chunks of code
              depending on the type. You may need to do some implicit casting, as in
              promoting an integer to a complex number, before you can actually perform
              the operation.


          o Polymorphism means using the same piece of code to operate on objects of
              different types. In LISP, cons is polymorphic because you can give it
              arguments of different types but it goes ahead and does its thing without
              worrying about it.


I'd say that just about hits the nail on the head (-: in my humble idiolect
:-). Overloading implies multiple implementation discriminating by type,
while polymorphism implies multiple interpretation (of the same code). I
don't feel, however, that we can allow the coercion of the arguments to make
an overload apply as part of the overloading process; rather, any function
that causes its arguments to be coerced is, if it is a proper property of
the function, POLYMORPHIC in that respect (though it may also be overloaded)
- because the coercion process is just a (trivial) mechanism to allow the
same implementation text to manipulate arguments of different types.


On the other hand, it should also be borne in mind that one (and to my mind,
the neatest) model of coercion is that it is itself the application of an
OVERLOADED function with a (textually) null name {footnote: We have to
resolve an ambiguity here, of course: between any two symbols, how many null
names did we read? Workable solutions, at different points along the
syntax/semantics scale, include requiring (a) that all coercion paths
commute (this is so semantic that you'd want to implement it by restricting
the forms or the directions of the coercions), (b) that all coercion paths,
including T->T, have length 1, or (c), and most subtly, that coercion paths
of length 1 are preferred to coercion paths of any other length (if we
include zero we can work implicit normalisers into this framework), and that
any ambiguity not resolved by this rule is forbidden.


Is this approach (a) stupid, (b) obvious, (c) known or (d) in need of
writing up someplace, does anyone know?}.


So:


    o Overloading is type-resolved multiple implementation.


    o Polymorphism is type-resolved multiple interpretation.


    o Coercion is, in effect, polymorphism implemented though CALL-SIDE
        normalisation by a distinguished overloaded function (unlike the
        other two, of course, this can't affect the result type, though in
        the other cases it need not, either).


    o There is also a fourth mechanism, dependent typing; this will
        allow us either to build explicitly type-parameterised functions
        (if we have dependent maps (ITT PI types)) or dynamically typed
        systems (if we have dependent products (SIGMA types)). {footnote:
        Going one step further and giving types properties, we get
        late-resolving object-orientation a la Smalltalk (which is NOT
        polymorphism because Smalltalk objects, since they "know" their
        class dynamically, only have a single type IMHI).}


Naively, there is no ambiguity at all; naive polymorphism would be compiled
by macro expansion (implying that C's .[.] operator is PRECISELY polymorphic
- it is, as I recall, surface syntax for *(.+.)), while naive overloading
can be seen as including parts of the type signature in an object's name.
That's pretty much the Ada model for both (I'm sure I'll be corrected if I
misremember me).


Things *can* get murky though. There are obviously other ways of getting
multiple implementations; any clausal-equational definition style will give
you this;-


0! = 1;
(n : N)' ! = n' * n!;


What this implies is that as soon as types acquire value-lke properties
(such as an however-indirectly user-accessible type comparison), the
distinction rapidly dissolves;


f (x : (X : TYPE)) = .if X = T .then tf x .else uf x .


provides only one body, but how different is it from


f (x : T) = tf x;
f (x : U) = uf x;


?


In case user-accessible type comparison seems far-fetched, incidentally,
note that the rather (IMHO) mathematically ill-considered unions of Algol68
relied on them, and that any language with non-injective coercions induces
(an admittedly not very usable) one.


Maybe I should also comment that from a type-inference point of view,
polymorphism is a little more straightforward, since it only implies that we
have some kind of quantification over types, while overloading implies that
we can discriminate them (a much stronger requirement, especially for those
of us uncomfortable with the everything-is-a-set outlook). But from an
implementation (particularly a compilation) standpoint, overloads are more
static and therefore nicer: you get less ucky descriptors and
quasi-interpretive code. In both domains the distinction is pretty important
from a TECHNICAL point of view, even though it can be
difficult-to-impossible for the user of a function to tell which he(gender
apology, but syntax requires)'s got.


Finally, we need to observe a curious fact: that while we can characterise
langauges according to which of polymorphism and overloading they provide to
the user, you would not normally have user-polymorphism without overloading
in the implementation. The reason for this is that any polymorphic text is
going to have to resolve to something executable, and unless you are going
to construct everything from combinators and operations manipulating objects
with homogeneous underlying representations (such as pointers), this implies
the existence of illative atoms (like, say, +) with overloaded
implementations.


(-:


      Having just taken a Linguistics class from Lakoff, I could explain all this
      away with a lot of learned talk about radial categories, and prototypical
      cases, and so forth ... but I'm really curious. What do YOU think the
      distinction is? Or isn't there one? Do you use these terms consistently?


I'd personally be interested and amused to hear you do just that; but
maybe this isn't the forum for it...? :-)


stephen p spackman stephen@estragon.uchicago.edu
--


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