Re: How make multifinished DFA for merged regexps?

Andy <borucki.andrzej@gmail.com>
Fri, 20 Dec 2019 16:29:01 -0800 (PST)

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How make multifinished DFA for merged regexps? borucki.andrzej@gmail.com (Andy) (2019-12-19)
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From: Andy <borucki.andrzej@gmail.com>
Newsgroups: comp.compilers
Date: Fri, 20 Dec 2019 16:29:01 -0800 (PST)
Organization: Compilers Central
References: 19-12-005
Injection-Info: gal.iecc.com; posting-host="news.iecc.com:2001:470:1f07:1126:0:676f:7373:6970"; logging-data="46163"; mail-complaints-to="abuse@iecc.com"
Keywords: lex, DFA
Posted-Date: 20 Dec 2019 19:33:10 EST
In-Reply-To: 19-12-005

Greedy algorithms match longest regexp. For example operators "+" and "++",
int numbers "123" and float numbers "123.456e3".
On '.' will finish state of number, but we will inside automata for float
number. But can be errors: after '.' will 'a'. We must backtrack to last
finished state? I want avoid backtracking. Maybe after backtracking we must
read chars from auxiliary token buffer instead of stream up to previous
position? But this complicated parsing.


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