Related articles |
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How detect cycle in grammar ? a.moderacja@gmail.com (Borneq) (2011-11-20) |
Re: How detect cycle in grammar ? haberg-news@telia.com (Hans Aberg) (2011-11-21) |
Re: How detect cycle in grammar ? gene.ressler@gmail.com (Gene) (2011-11-21) |
Re: How detect cycle in grammar ? anton@mips.complang.tuwien.ac.at (2011-11-22) |
Re: How detect cycle in grammar ? a.moderacja@gmail.com (Borneq) (2011-11-23) |
Re: How detect cycle in grammar ? a.moderacja@gmail.com (Borneq) (2011-11-24) |
Re: How detect cycle in grammar ? quinn_jackson2004@yahoo.ca (Quinn Tyler Jackson) (2011-11-25) |
Re: How detect cycle in grammar ? gene.ressler@gmail.com (Gene) (2011-11-27) |
Re: How detect cycle in grammar ? gene.ressler@gmail.com (Gene) (2011-11-27) |
Re: How detect cycle in grammar ? anton@mips.complang.tuwien.ac.at (2011-11-28) |
Re: How detect cycle in grammar ? gah@ugcs.caltech.edu (glen herrmannsfeldt) (2011-11-29) |
Re: How detect cycle in grammar ? paul@paulbmann.com (Paul B Mann) (2011-12-01) |
[2 later articles] |
From: | Borneq <a.moderacja@gmail.com> |
Newsgroups: | comp.compilers |
Date: | Thu, 24 Nov 2011 09:24:07 -0800 (PST) |
Organization: | Compilers Central |
References: | 11-11-041 11-11-045 |
Keywords: | parse, theory |
Posted-Date: | 25 Nov 2011 22:18:32 EST |
On 21 Lis, 19:20, Gene <gene.ress...@gmail.com> wrote:
> As I recall the algorithm starts with the lhs's of rules that expand
> entirely to terminals (including epsilon) and recursively marks
> nonterminals that have a rule where the entirely right hand side is
> either marked or terminal. When you're done marking in this manner,
> the unmarked nonterminals are useless. All rules involving them can
> be deleted without changing the represented language. If the start
> symbol is unmarked, the language is empty.
I found http://programming4.us/desktop/408.aspx section "4 Reduction
of Grammar"
I interpret this: we mark nonterminal as usable if any its production
contains only terminals or marked previously nonterminals.
But what if nonterminal has one using production and one useless? For
example
A->A
A->B
B->b
How eliminate A->A ?
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