Related articles |
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Decidability of Deterministic Context-Free Languages ott@mirix.org (Matthias-Christian Ott) (2010-06-01) |
Re: Decidability of Deterministic Context-Free Languages gneuner2@comcast.net (George Neuner) (2010-06-01) |
Re: Decidability of Deterministic Context-Free Languages gene.ressler@gmail.com (Gene) (2010-06-01) |
Re: Decidability of Deterministic Context-Free Languages torbenm@diku.dk (2010-06-02) |
Re: Decidability of Deterministic Context-Free Languages ott@mirix.org (Matthias-Christian Ott) (2010-06-02) |
Re: Decidability of Deterministic Context-Free Languages gene.ressler@gmail.com (Gene) (2010-06-06) |
Re: Decidability of Deterministic Context-Free Languages gneuner2@comcast.net (George Neuner) (2010-06-07) |
From: | torbenm@diku.dk (Torben Ęgidius Mogensen) |
Newsgroups: | comp.compilers |
Date: | Wed, 02 Jun 2010 16:28:23 +0200 |
Organization: | UNI-C |
References: | 10-06-003 |
Keywords: | parse, theory |
Posted-Date: | 03 Jun 2010 15:08:02 EDT |
Matthias-Christian Ott <ott@mirix.org> writes:
> it is generally not decidable whether a context-free language is
> deterministic. That means it is not decidable whether a grammar is an
> LR(k) grammar.
>
> However, a LR(k) parser can indicate conflicts in the parsing table
> and detect if a grammar is not a LR(k) grammar.
>
> This seems to be a contradiction.
Not at all. A grammar is deterministic if there exists a k such that
the grammar is LR(k). Making a LR(k) parser answers the question only
for a specific k.
Once you add the existential quantifier, you imply an unbounded search,
so the question is only semi-decidable: If the answer is "yes", you will
eventually get it, but if the answer is "no", you will never know.
You can look at it this way: If the grammar is not deterministic, how
will you prove it?
Torben
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