Related articles |
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[2 earlier articles] |
Re: LR(k) parser generator for k>1? joevans@gmail.com (Jason Evans) (2008-05-20) |
Re: LR(k) parser generator for k>1? parrt@cs.usfca.edu (parrt) (2008-05-20) |
Re: LR(k) parser generator for k>1? cfc@shell01.TheWorld.com (Chris F Clark) (2008-05-28) |
Re: LR(k) parser generator for k>1? txchen@gmail.com (Thomas Chen) (2008-05-29) |
Re: LR(k) parser generator for k>1? kamalpr@hp.com (kamal) (2008-06-03) |
Re: LR(k) parser generator for k>1? cfc@shell01.TheWorld.com (Chris F Clark) (2008-06-03) |
Re: LR(k) parser generator for k>1? FSet.SLB@gmail.com (Scott Burson) (2008-06-08) |
From: | Scott Burson <FSet.SLB@gmail.com> |
Newsgroups: | comp.compilers |
Date: | Sun, 8 Jun 2008 20:20:58 -0700 (PDT) |
Organization: | Compilers Central |
References: | 08-05-075 |
Keywords: | parse, LR(1) |
Posted-Date: | 09 Jun 2008 19:05:02 EDT |
On May 18, 2:27 pm, Tom <txc...@gmail.com> wrote:
> I have searched on Internet and the comp.compilers news group for
> LR(k) parser generator implementation where k > 1.
Another approach is regular lookahead, where for each conflict the
parser generator attempts to construct a regular expression to be
applied to the lookahead tokens such that the success or failure of
the match will disambiguate the conflict. You can find some papers on
this by Bermudez and Schimpf.
-- Scott
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