Re: fully parenthesized expression?

"Mr.E" <mr.waverlye@verizon.net>
10 Mar 2007 21:35:11 -0500

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fully parenthesized expression? mr.waverlye@verizon.net (Mr.E) (2007-03-03)
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Re: fully parenthesized expression? mr.waverlye@verizon.net (Mr.E) (2007-03-08)
Re: fully parenthesized expression? mailbox@dmitry-kazakov.de (Dmitry A. Kazakov) (2007-03-08)
Re: fully parenthesized expression? mr.waverlye@verizon.net (Mr.E) (2007-03-10)
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From: "Mr.E" <mr.waverlye@verizon.net>
Newsgroups: comp.compilers
Date: 10 Mar 2007 21:35:11 -0500
Organization: Compilers Central
References: 07-03-01507-03-026 07-03-033
Keywords: parse
Posted-Date: 10 Mar 2007 21:35:11 EST

> The variant with queue (pseudo-code):
>
> Stack >> Right;
> Stack >> Left;
> Stack << Left * Right;
> '(' >> Qutput; // The left side of the output queue accessed
> Output << '*';
> Output << Right;
> Output << ')';
>
> Once you finished, you can print Output.
>
> The variant with source locations:
>
> Stack >> Right;
> Stack >> Left;
> Stack <<
> Operand
> ( Left.Value * Right.Value,
> Left.Location + Right.Location + Location_of_Multiply
> );
>
[SNIP]


I believe I understand now. Hopefully this weekend I will try it out.


Thank you very much,




W.


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