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| Related articles |
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| RegExp to match against RegExp's alex.habar.nam@gmail.com (whiskey) (2007-03-01) |
| Re: RegExp to match against RegExp's JoelCSalomon@Gmail.com (Joel C. Salomon) (2007-03-03) |
| Re: RegExp to match against RegExp's rsc@swtch.com (Russ Cox) (2007-03-05) |
| Re: RegExp to match against RegExp's dickey@saltmine.radix.net (Thomas Dickey) (2007-03-08) |
| Re: RegExp to match against RegExp's alex.habar.nam@gmail.com (whiskey) (2007-03-14) |
| From: | "whiskey" <alex.habar.nam@gmail.com> |
| Newsgroups: | comp.compilers |
| Date: | 1 Mar 2007 01:08:36 -0500 |
| Organization: | Compilers Central |
| Keywords: | lex, question |
| Posted-Date: | 01 Mar 2007 01:08:36 EST |
Hello
I'm not sure I'm in the right place, however my question is somehow
related to an interpreter. Not a "must do", rather a "wanna know". So,
my question is: how would a regular expression that matches a regular
expression look like ?
Given a string like "$myFoo =~ /regexp/" *, I want to match the /
regexp/ part. I can't just use something like /\/[^\/]*\// because my /
regexp/ can be /^http:\/\// and it will only return "/^http:/".
* no, I'm not writing a Perl interpreter :-)
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