Re: Is this a form of Data Flow Analysis, and what is the proper way solution to the problem?

"Oliver Wong" <owong@castortech.com>
28 Jan 2006 15:18:17 -0500

          From comp.compilers

Related articles
[3 earlier articles]
Re: Is this a form of Data Flow Analysis, and what is the proper way s DrDiettrich@compuserve.de (Hans-Peter Diettrich) (2006-01-17)
Re: Is this a form of Data Flow Analysis, and what is the proper way s paolo.bonzini@gmail.com (2006-01-17)
Re: Is this a form of Data Flow Analysis, and what is the proper way s owong@castortech.com (Oliver Wong) (2006-01-20)
Re: Is this a form of Data Flow Analysis, and what is the proper way s gneuner2@comcast.net (George Neuner) (2006-01-26)
Re: Is this a form of Data Flow Analysis, and what is the proper way s paolo.bonzini@gmail.com (2006-01-26)
Re: Is this a form of Data Flow Analysis, and what is the proper way s pohjalai@cc.helsinki.fi (A Pietu Pohjalainen) (2006-01-26)
Re: Is this a form of Data Flow Analysis, and what is the proper way s owong@castortech.com (Oliver Wong) (2006-01-28)
Re: Is this a form of Data Flow Analysis, and what is the proper way s pohjalai@cc.helsinki.fi (A Pietu Pohjalainen) (2006-02-03)
| List of all articles for this month |
From: "Oliver Wong" <owong@castortech.com>
Newsgroups: comp.compilers
Date: 28 Jan 2006 15:18:17 -0500
Organization: GlobeTrotter
References: 06-01-037 06-01-055 06-01-079
Keywords: analysis
Posted-Date: 28 Jan 2006 15:18:17 EST

"A Pietu Pohjalainen" <pohjalai@cc.helsinki.fi> wrote
> paolo.bonzini@gmail.com wrote:
>>> In the statement:
>>> z = y = x;
>>> Which of the following outputs would be more "correct"?
>>>
>>> * There is a read from x, which leads to a write to y.
>>> * There is a write to y.
>>> * There is a read from y, which leads to a write to z.
>>> * There is a write to z.
>
>> This one, according to the JLS.
>
> JLS = Java Language Specification ?
>
> Java compiler does to bytecode level:
> read x;
> duplicate;
> write y;
> write z;
>
> There is no read from y.


        Note sure about the bytecode, but from the JLS 3rd edition:


http://java.sun.com/docs/books/jls/third_edition/html/expressions.html#15.26


<quote>
a=b=c means a=(b=c), which assigns the value of c to b and then assigns the
value of b to a.
</quote>


        Probably my original terminology or phrasing "there is a read etc." was
flawed, which may have caused some confusion.


        - Oliver


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