Related articles |
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Return value address nicolas_capens@hotmail.com (2004-09-07) |
Re: Return value address christoph.neubauer@siemens.com (Christoph Neubauer) (2004-09-08) |
Re: Return value address tmk@netvision.net.il (2004-09-13) |
Re: Return value address Nicola.Musatti@ObjectWay.it (2004-09-14) |
Re: Return value address christoph.neubauer@siemens.com (Christoph Neubauer) (2004-09-21) |
Re: Return value address kamalp@acm.org (2004-09-21) |
From: | "Christoph Neubauer" <christoph.neubauer@siemens.com> |
Newsgroups: | comp.compilers |
Date: | 21 Sep 2004 22:17:25 -0400 |
Organization: | Siemens AG Austria |
References: | 04-09-054 04-09-069 04-09-100 |
Keywords: | code |
Posted-Date: | 21 Sep 2004 22:17:25 EDT |
"Nicola Musatti" <Nicola.Musatti@ObjectWay.it> wrote in message
> "Christoph Neubauer" <christoph.neubauer@siemens.com> wrote
> > What about a stack model, that allocates:
> >
> > r allways at 0
> > arguments starting at 4
> > local variables afterwards
> > temp variables afterwards
>
> In my ignorance I thought that just about every compiler worked in
> this way, except maybe when return value and arguments are directly
> allocated into registers. Are there reasons to do otherwise?
Hi Nicola !
I don't know many different compilers and/or stack models.
All of them return function result either on '0' or in register(s).
Further I don't know any reason to do it some other way.
> > [It also seemed to me that the obvious solution is for the caller to
> > allocate the return value cell. -John]
>
> Wouldn't this also give the opportunity to optimize it away, e.g. by
> directly using the variable to which the function result is assigned?
>
As I see it:: No.
If you generate code for a certain function, you don't know anything
about the 'dynamic surrounding', where the function is called from !
(Despite some knowledge/optimizations for recursive calls)
What you (maybe ?) could do is:
Pass the address of the variable to the function call (as hidden argument)
Use this address for -indirect- assignment of the result.
--> No performance win at all
Kind regards,
Chris
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