Re: Are there any tools that can compare two source files

Tim Josling <tej@melbpc.org.au>
22 Dec 2001 23:02:54 -0500

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Related articles
[3 earlier articles]
Re: Are there any tools that can compare two source files nmm1@cus.cam.ac.uk (2001-12-19)
Re: Are there any tools that can compare two source files joachim_d@gmx.de (Joachim Durchholz) (2001-12-20)
Re: Are there any tools that can compare two source files torbenm@eir.diku.dk (2001-12-20)
Re: Are there any tools that can compare two source files Martin.Ward@durham.ac.uk (2001-12-20)
Re: Are there any tools that can compare two source files thp@cs.ucr.edu (2001-12-20)
Re: Are there any tools that can compare two source files idbaxter@semdesigns.com (Ira D. Baxter) (2001-12-22)
Re: Are there any tools that can compare two source files tej@melbpc.org.au (Tim Josling) (2001-12-22)
| List of all articles for this month |
From: Tim Josling <tej@melbpc.org.au>
Newsgroups: comp.compilers
Date: 22 Dec 2001 23:02:54 -0500
Organization: Melbourne PC User Group
References: 01-12-027 01-12-058 01-12-092
Keywords: tools
Posted-Date: 22 Dec 2001 23:02:54 EST

Not to forget of course that all 'real' computer programs have finite
memory and are thus actually state machines. To be a Turing machine
you have to have access to infinite memory, and that is very
expensive, even today.


If the size of memory including disk and tapes and registers is n bits,
then a deterministic program must either loop, halt or crash in 2**n
instructions/states.


In this context, equivalence is perfectly decidable by a program with
slightly more memory. Might take a while though.


Tim Josling


"Torben Ęgidius Mogensen" wrote:


> Sarath Kumar <sarath_kumar@mentorg.com> writes:
>
> > Generalizing the problem refers to the problem of finding the
> > semantic equivalence of two programs. Is this possible?? As the
> > theorists go this is very tough and not possible in polynomial time.
>
> If the language is Turing-complete, equivalence is undecidable.
>
> This doesn't man that you can never the decide if two programs are
> equivalent, but it means that there are cases where you can't.
>
> Some languages, e.g., regular expressions, have decidable equivalence,
> but even for these, polynomial time normally isn't enough.
>
> Torben Mogensen (torbenm@diku.dk)


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