Related articles |
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Making an NFA from a grammar meson@cyber.net.pk (2001-08-02) |
Re: Making an NFA from a grammar martijn@shop.com (Martijn de Vries) (2001-08-15) |
Re: Making an NFA from a grammar joachim_d@gmx.de (Joachim Durchholz) (2001-08-17) |
Re: Making an NFA from a grammar vannoord@let.rug.nl (2001-08-18) |
From: | Martijn de Vries <martijn@shop.com> |
Newsgroups: | comp.compilers |
Date: | 15 Aug 2001 01:42:16 -0400 |
Organization: | XS4ALL Internet BV |
References: | 01-08-008 |
Keywords: | lex, parse |
Posted-Date: | 15 Aug 2001 01:42:16 EDT |
compiler <meson@cyber.net.pk> wrote:
> In Sec 4.3 of Compilers Principles, Techniques, and Tools, the authors
> give an algorithm for converting an NFA into a grammar that generates
> the same language as recognized by the NFA. Is there any algorithm,
> which when given a grammar, converts it back to an NFA, IFF the
> grammar represents a regular language. I know it is easy for grammars
> of the sort A -> a B since this is the kind of grammar which the above
> mentioned algorithm generates, but is there an algorithm that does
> this for the general case? Where the grammar productions might not be
> in the for A -> a B but the grammar represents a regular language?
As far as I know, a regular grammar may only contain productions of the
form "A -> a B" and "A -> a". So if you want to write an algorithm which
constructs an NFA out of a regular grammar you only need to consider these
two production forms.
Regards,
Martijn de Vries
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