|Preprocessing ## DrDiettrich1@netscape.net (Hans-Peter Diettrich) (2017-05-13)|
|Re: Preprocessing ## DrDiettrich1@netscape.net (Hans-Peter Diettrich) (2017-05-15)|
|Re: Preprocessing ## email@example.com (Kaz Kylheku) (2017-05-15)|
|Re: Preprocessing ## firstname.lastname@example.org (George Neuner) (2017-05-15)|
|From:||Hans-Peter Diettrich <DrDiettrich1@netscape.net>|
|Date:||Sat, 13 May 2017 08:49:36 +0200|
|Injection-Info:||miucha.iecc.com; posting-host="news.iecc.com:2001:470:1f07:1126:0:676f:7373:6970"; logging-data="6245"; mail-complaints-to="email@example.com"|
|Posted-Date:||14 May 2017 21:21:48 EDT|
How is the C preprocessor assumed to handle the ## concatenation operator?
In the Windows headers I found macros like
#define foo(x) bar(##baz(x))
where an expansion into ... (baz ... doesn't make sense, because "(baz"
is not a valid preprocessor token. Can somebody explain the meaning and
handling of such constructs?
DoDi [I would guess that some macro between ( and ## expanded to
nothing. Or it could just be one of those text editing errors. -John]
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