Re: flex default rule

Dimitri Maziuk <dmaziuk@bmrb.wisc.edu>
8 Apr 2006 17:09:31 -0400

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Re: flex default rule dmaziuk@bmrb.wisc.edu (Dimitri Maziuk) (2006-04-08)
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From: Dimitri Maziuk <dmaziuk@bmrb.wisc.edu>
Newsgroups: comp.compilers
Date: 8 Apr 2006 17:09:31 -0400
Organization: only myself
References: 06-04-001 06-04-023
Keywords: lex
Posted-Date: 08 Apr 2006 17:09:31 EDT

Dimitri Maziuk sez:
> Dimitri Maziuk sez:
>> Hi all,
>>
>> here's what I can't quite figure out:
>
> Scratch that. I've been staring at my screen too long.
>
> This is a backport from Java, and JFlex has a couple of differences
> from flex. Most importantly, when more than one rule matches, JFlex
> will apply the first rule in the set whereas flex applies the longest
> matching one.


Or, rather, JFlex has a "[^]" that's equivalent to ".|\n" -- I initially
replaced it with "." in flex specs and it stopped matching tokens with
newlines it 'em. Surprise, surprise.


There was a braino in my OP, too: the 3rd rule was supposed to be in
<SEMI>, not <INITIAL>.


Dima
--
      Double d = new Double(2.0);
      d = new Double(d.doubleValue() * d.doubleValue());
I regard Double variables as mutable, considering this one started as 2.0 and
ended up as 4.0. -- Brendan Guild

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