|How to use IBURG to exchange tree nodes? email@example.com (2003-11-21)|
|Re: How to use IBURG to exchange tree nodes? firstname.lastname@example.org (Christian Lindig) (2003-12-03)|
|From:||email@example.com (Alan Jiang)|
|Date:||21 Nov 2003 00:45:42 -0500|
|Posted-Date:||21 Nov 2003 00:45:42 EST|
For example: (all variables are int type)
a-c+d is expressed as tree (a-c)+d, but I hope IBURG can transform it
Another example is: a+b+c+d is originally expressed as tree
((a+b)+c)+d, can I write IBURG rules to change the tree to
Does it possible for IBURG rules to do the above job? Or it is just
above the ability of IBURG?
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